36c^2+3=29

Solution for 36c^2+3=29 equation:

36c^2+3=29

We move all terms to the left:

36c^2+3-(29)=0

We add all the numbers together, and all the variables

36c^2-26=0

a = 36; b = 0; c = -26;
Δ = b2-4ac
Δ = 02-4·36·(-26)
Δ = 3744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3744}=\sqrt{144*26}=\sqrt{144}*\sqrt{26}=12\sqrt{26}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{26}}{2*36}=\frac{0-12\sqrt{26}}{72}
=-\frac{12\sqrt{26}}{72}
=-\frac{\sqrt{26}}{6}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{26}}{2*36}=\frac{0+12\sqrt{26}}{72}
=\frac{12\sqrt{26}}{72}
=\frac{\sqrt{26}}{6}
$